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I assumed the cryptograph to be English.
"You observe there are no divisions between the words. Had there been
divisions, the task would have been comparatively easy. In such case
I should have commenced with a collation and analysis of the shorter
words, and, had a word of a single letter occurred, as is most likely,
(
a or I, for example,) I should have considered the solution as assured.
But, there being no division, my first step was to ascertain the
predominant letters, as well as the least frequent. Counting all, I
constructed a table, thus:
Of the character 8 there are 33.
;
"
26.
4
)
"
"
19.
κΆ€
16.
13.
12.
11.
*
"
5
6
"
"
163
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