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The colour of derived shadows is always affected by that of the body
towards which they are cast. To prove this: let an opaque body be
placed between the plane s c t d and the blue light d e and the
red light a b, then I say that d e, the blue light, will fall on
the whole surface s c t d excepting at o p which is covered by
the shadow of the body q r, as is shown by the straight lines d q
o e r p. And the same occurs with the light a b which falls on
the whole surface s c t d excepting at the spot obscured by the
shadow q r; as is shown by the lines d q o, and e r p. Hence
we may conclude that the shadow n m is exposed to the blue light
d e; but, as the red light a b cannot fall there, n m will
appear as a blue shadow on a red background tinted with blue,
because on the surface s c t d both lights can fall. But in the
shadows only one single light falls; for this reason these shadows
are of medium depth, since, if no light whatever mingled with the
shadow, it would be of the first degree of darkness &c. But in the
shadow at o p the blue light does not fall, because the body q r
interposes and intercepts it there. Only the red light a b falls
there and tinges the shadow of a red hue and so a ruddy shadow
appears on the background of mingled red and blue.
The shadow of q r at o p is red, being caused by the blue light
d e; and the shadow of q r at o' p' is blue being caused by
the red light a b. Hence we say that the blue light in this
instance causes a red derived shadow from the opaque body q' r',
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